How to long press until visibility of some element

Support
1

I was wondering if i can you touch action to perform long press until visibility of some element or element to be clickable …etc

            touch.longPress(LongPressOptions.longPressOptions()
            .withElement(ElementOption.element (selectSFD)))
            .waitAction(wait.until(ExpectedConditions.visibilityOf(installingModal)))
            .perform ();
2

@Aleksei
could you help me with this

3

never tried. i believe it not possible to make.

2 Likes
4

This code won’t work. perform will be always executed only after wait.until is completed (or fail).

1 Like
5

This kind of UI interaction question comes up so often, I have to wonder what people were thinking when they signed up at this automation job. We need to make app develoeprs responsible for making apps easier to test. I really do feel sorry for you here, this is pretty common as a automation blocker. I really do feel your pain, I used to let this block me in the past.

You could try:

  1. get the developer to export a UI intent that fires the BH you want to validate.
  2. get them to give you another way of testing the same functionality
  3. decide whether your UI has got dissability/acessibility issues and start over
  4. Dont automate this test case in the way you are , but automate the same check in another way/route entirely.

When we automate the GUI, we are not really checking anything. Try and get your team to change their approach to “testing”.

6

what im saying is completely legit for my scenario, we have a responsive app that doing some action when you long press on some element and long press duration is random, thats why i want to make long press is more smart instead of stating specific long press duration

first you have to know the full scenario that is happening,

7

You can perform long press and try to find len(new_element) in a loop.

from appium.webdriver.common.touch_action import TouchAction
self.actions = TouchAction(driver)

element = self.driver.find_element_by_xxx('locator')
for i in range(5):
   self.actions.long_press(element).release().perform()
   element1 = self.driver.find_elements_by_xxx('locator1')
   if len(element1):
               break
   take action on new element