How to write xpath if parent and childs having the same class name and store the elements in the list

Support
1

Hi

How to find out xpath for the below situation for the native apps for the child and parent class name are same.
.

trying with class name able to retrieving the first row only. need to retrieve all rows.

can any one help me

2

Hi Pradeep,

Can you upload the Xpath of 2 or 3 cells than we can make a strategy to solve you issue,
meanwhile, i believe there two conditions are possible i.e…

1.All cell have same xpath-> In this case you can use
List element=driver.findElements(By.xpath(“xpath”)); , it will return list of all cell,

  1. Cell have different xpath :You can write Relative xpath to perform any action.

I think it will work please let me know you side.

Thanks

3

Hi dharam ,

am new to appium,i have tried with the below xpath

findElementsByAndroidUIAutomator(“UiSelector().className(“classname[@index]””); and able to get only first row not able to get all the rows in the list…

could you help how to write relative xpath.
thanks

4

if am understand correct you are passing index of cell than you are getting only that row , instead of passing index try below code, i think it will help,

“List<Web_Element> elementsList = driver.findElements(By
.className(className));”

for (WebElement webElement : elementsList)
{
System.out.println(webElement);
}

5

Hi dharam,

still not able to get the LinearLayout[index 0 to 9] elements.

6

String xpath = “//android.widget.ListView/descendant::android.widget.LinearLayout”;

List <WebElement> ListByXpath = driver.findElements(By.xpath(xpath));

See if that works

1 Like
7

Thanks Umar. able to get the list content

Need one more clarification regarding “//android.widget.ListView/descendant::android.widget.LinearLayout”; here to get another child LinearLayout" content.

Listview->Layout->textview->Layout

8

It shall return you all VISIBLE linearLayout elements. If there are more and are not visible Appium won’t return those.

9

Hi Umar ,
Am able to find the index of the Layout …
Ex:index=5

then i have to click each and every layout by using for loop with xpath is this workable.

Thanks

10

Hi Pradeep

Give it a try and let us know if that works for you

11

Hi Umar,

I tried with below: but not working …if possible help me out of it.

List layoutindex=null;

	    layoutindex= d.findElementsByXPath("//android.widget.ListView/*");
	   
	  
	 for (int i=0;i<=layoutindex.size()-1;i++)
	 {
      d.findElementByXPath("//android.widget.ListView/android.widget.LinearLayout[@index='i']/*").click();

	 }
12

Please check this. Index strategy might not work. Get the list of elements and then loop it through and click the desired element. There might be a good chance you have to swipe if that element is not in screen view.

13

Hi umer,
List ListByXpath = driver.findElements(By.xpath(xpath)); in this statement what is the exact meaning of By.xpath(xpath)…
could you plz.

14

Hi umar ,

For the above post i understood the xpath difference,
am able to find out the index by using your statement also… but the thing is i need to click each index one by one…
am able to click only index=0 only …
Please help me to out of it.

15

How many elements are there in the list. If it has only one then only index 0 is available.

16

Actually its having 4…

17

You should be able to click on all of 4 elements. If size is 4 then you have 5 elements. Loop it through and click on each element.

list-variable-name.get(i).click;

18

Hi umer,
Same statement am using and posted above post only …
But am able to click on index 0 only…
for 1,2,3 coming out of the loop and displaying as element not found error

19

Can you send me the apk and necessary information. I will try to see what is going on.

20

Hi Guys , our team has found some thing that is useful to all of you about the query topic : for finding the xpath of child element inside any parent element :
use : driver.findElement(By.xpath(OR.getProperty(parent element))).findElement(By.id(“child element property”))